5(x^2+12x+36)=0

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Solution for 5(x^2+12x+36)=0 equation: 



5(x^2+12x+36)=0

We multiply parentheses

5x^2+60x+180=0

a = 5; b = 60; c = +180;
Δ = b2-4ac
Δ = 602-4·5·180
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-60}{10}=-6$

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